Number is Armstrong or not in C#

/*
Summary: Check whether a number is armstrong or not.
A number is armstrong if the sum of cubes of individual digits of
a number is equal to the number itself.
For example 371 is an armstrong number as 27 + 343 + 1 = 371.
*/

#include <stdio.h>

int main()
{
int number, sum = 0, temp, remainder;

printf("Enter an integer\n");
scanf("%d",&number);

temp = number;

while( temp != 0 )
{
remainder = temp%10;
sum = sum + remainder*remainder*remainder;
temp = temp/10;
}

if ( number == sum )
printf("Entered number is an armstrong number.\n");
else
printf("Entered number is not an armstrong number.\n");

return 0;
}


_______________________________OUPUT______________________________
Enter an integer
321
Entered number is not an armstrong number.




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